This morning Sam’s dad decided to test his son’s math progress at school.
He put six pieces of clothes in front of Sam, each with a different number of pockets.
Top wear: polo – 1 pocket, shirt – 2, and hoodie – 3.
Bottom wear: khakis – 4 pockets, jeans – 5, and shorts – 6.
Assuming the number of pockets in top wear is X, and in bottom wear – Y, Sam’s challenge was to figure out what two pieces he had to put on that morning in order two conditions are met:
1. The sum (X+Y) doesn’t appear with any other combination of a top and a bottom wear.
2. The multiplication of the pockets (X*Y) is bigger than their sum (X+Y).
Dad told Sam he would receive the pocket money in the amount of (X*Y) for the right answer. Knowing that Sam didn’t disappoint his dad, how much money he earned that morning?
There are only 9 combinations of the top and bottom wear with the respective numbers of pockets:
A) Polo + Khakis = 1 + 4 = 5.
B) Polo + jeans = 1 + 5 = 6.
C) Polo + shorts = 1 + 6 = 7.
D) Shirt + khakis = 2 + 4 = 6.
E) Shirt + jeans = 2 + 5 = 7.
F) Shirt + shorts = 2 + 6 = 8.
G) Hoodie + khakis = 3 + 4 = 7.
H) Hoodie + jeans = 3 + 5 = 8.
I) Hoodie + shorts = 3 + 6 = 9.
Only options (A) and (I) are unique and only for option (I) its multiplication 3*6 is bigger than its sum 3+6. Thus, the correct option is (I) and Sam earned $18 as his pocket money for the day.