Solution Step 0/0
This two-cube calendar numerically represents every day in a month. What are the four digits that are hidden from the view on the left cube, and the three on the right one?
Explanations
Each cube must bear a 0, 1 and 2. This leaves only six faces for the remaining seven digits. The same face can be used for 6 and 9.The puzzle shows 3, 4, 5 on the right cube. Therefore, its hidden faces must be 0, 1 and 2.
On the left cube the 1 and 2 can be seen. So its hidden faces must be 0, 6 (=9), 7 and 8.
Check L:3-4-7-8. R:1-2-6
Check L:3-6-7-8. R:0-1-3
Check L:0-6-7-8. R:0-1-2
Check L:5-6-7-8. R:0-1-2
