by Serhiy Grabarchuk Jr

Solution Step 0/0

This morning Sam’s dad decided to test his son’s math progress at school.

He put six pieces of clothes in front of Sam, each with a different number of pockets.

Top wear: polo – 1 pocket, shirt – 2, and hoodie – 3.

Bottom wear: khakis – 4 pockets, jeans – 5, and shorts – 6.

Assuming the number of pockets in top wear is X, and in bottom wear – Y, Sam’s challenge was to figure out what two pieces he had to put on that morning in order two conditions are met:

1. The sum (X+Y) doesn’t appear with any other combination of a top and a bottom wear.

2. The multiplication of the pockets (X*Y) is bigger than their sum (X+Y).

Dad told Sam he would receive the pocket money in the amount of (X*Y) for the right answer. Knowing that Sam didn’t disappoint his dad, how much money he earned that morning?

There are only 9 combinations of the top and bottom wear with the respective numbers of pockets:

A) Polo + Khakis = 1 + 4 = 5.

B) Polo + jeans = 1 + 5 = 6.

C) Polo + shorts = 1 + 6 = 7.

D) Shirt + khakis = 2 + 4 = 6.

E) Shirt + jeans = 2 + 5 = 7.

F) Shirt + shorts = 2 + 6 = 8.

G) Hoodie + khakis = 3 + 4 = 7.

H) Hoodie + jeans = 3 + 5 = 8.

I) Hoodie + shorts = 3 + 6 = 9.

Only options (A) and (I) are unique and only for option (I) its multiplication 3*6 is bigger than its sum 3+6. Thus, the correct option is (I) and Sam earned $18 as his pocket money for the day.

Check Between $5 and $8

Check Between $9 and $12

Check Between $13 and $16

Check Between $17 and $20