by Serhiy Grabarchuk Jr. 

A company has just rented a new floor in the building. The fiveroom floor, shown in the center, is designated for the company’s new analytical department, consisting of 6 employees. Under the plan employees should be distributed among three rooms in ratio 1:2:3, the fourth room should be the Copier room (C), and the fifth one  the Kitchen (K).
Company’s top management appointed its Chief office planner (COP) to organize the floor in such a way that the sum of the distances (doortodoor) per employee from his/her room to the Kitchen is the longest possible, while the sum of the distances per employee from his/her room to the Copier room is the shortest possible. In the fourroom floor Example the sum of the distances from the employees’ rooms to K is 1*X+2*Y, while the sum of the distances to C is 1*Y+2*X. Since Y is approx 1.4X, the sum of the distances to K is approximately 3.8 units and to C  3.4, which is not necessarily the optimal solution. Can you help COP to solve this Puzzle 1 for the fiveroom floor?
Meanwhile, being a staunch union member in the past, COP quickly persuaded the management to put aside that floor plan. To make the kitchen closer to the folks, he suggested a new floor plan arguing it would raise the labor productivity. Under it the floor has to be designed in such a way that the sum of the distances to K when added to the sum of the distances to C would produce the least possible final distance. In the fourroom floor Example the final distance is 7.2 units (3.8+3.4), which is not the least one for the floor. Can you help COP to solve this Puzzle 2 for the fiveroom floor?



